Need a little help with solving the triangles Bearings, triangles, distances... oh my!!!?

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A plane flying a straight course observes a mountain at a bearing of 35.1° to the right of its course. At

that time the plane is 6 kilometers from the mountain. A short time later, the bearing to the mountain

becomes 45.1°. How far is the plane from the mountain when the second bearing is taken (to the

nearest tenth of a km)?

possible answers are

1) 7.4 kilometers

2) 4.9 kilometers

3) 3.2 kilometers

4) 8.1 kilometers




  1. 6 x (sin 35.1) / sin 134.9

    4.9 kilometers.

    hv used sin formula.

    Sin angle/ opp side = sin second angle/ opp side to second angle = sin third angle/ side opp to third angle.

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