I need help with math ?????????????

Question

Q is the midpoint of pq (with a line over it) p has cordonites -3 -1 and Q has cordonites 0,1 find the cordonites of R

Thanks

Answer 1

find the slope of the line first

delta Y / delta x

-1-1/-3 = 2/3

so point R has to be up 2 over 3, so R(2,4)

Answer 2

To find the midpoint, use the midpoint equation:

midpoint: ((x1 + x2)/2, (y1 + y2)/2)

(x1, y1) = (-3, -1)

(x2, y2) = (0, 1)

R = ((-3 + 0)/2, (-1 + 1)/2)

R = ((-3/2), 0/2)

R = (-3/2, 0)

This is the answer if R is the midpoint of PQ.

If Q is the midpoint of PR, the coordinates of P are (-3, -1) and the coordinates of Q are (0, 1), then:

We can still use the midpoint formula:

((x1 + x2)/2, (y1 + y2)/2) = Q = (0, 1)

(x1, y1) = (-3, -1)

(x2, y2) = R

((-3 + x2)/2, (-1 + y2)/2) = (0, 1)

(-3 + x2)/2 = 0

-3 + x2 = 0

x2 = 3

(-1 + y2)/2 = 1

-1 + y2 = 2

y2 = 3

Coordinates for R: (3, 3)

Answer 3

The slope of the line segment is 2/3 (y increases by 2 as x increases by 3). For point Q to be the midpoint, point R must be the same distance from point Q as point P is.

The x distance from P to Q is +3, the y distance is +2. That means point R must be 3 units farther right than point Q (x = 3). Point R must also be 2 units above point Q (y = 3).

Point R has the coordinates (3, 3).

[added]

Was that a typo when you wrote "Q is the midpoint of pq"?

You did mean "Q is the midpoint of PR", right?

Answer 4

R = (2,4)

answer mine please!

http://answers.yahoo.com/question/index;...

Answer 5

6 4 are the co or inate of the point