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a solution hydroxide solution is prepared by dissolving 6 g NaOH in 1 L of solution. what is the molar concentration of OH- in the soution? what is the pOH and the ph of the solution? what is the hydrogen ion concentration in the solution

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  1. Molarity = moles NaOH/liters of solution

    You know that you have 6 g of NaOH, so you need to convert to moles using the gram formula mass, which is 40 g/mol

    6 g NaOH x 1 mol/40 g = 0.15 mol NaOH

    Good so far? Now, just plug that in to find the molarity:

    0.15 mol/ 1 L = 0.15 M

    Since NaOH is a strong base, it will dissolve completely in solution, so you will have [Na+]=0.15 M and [OH-]=0.15 M.

    To find the pOH, you follow the formula:

    pOH = -log[OH-]

    pOH=-log(.15)= 0.82

    pH + pOH must = 14, so:

    pH= 14- 0.82 = 13.18. A high pH is expected since this is a strong base and a higher pH indicates a higher basicity.

    Finally, since [H+][OH-] = 1 x 10^-14, plug in your [OH-] value and find [H+].

    HOPE THIS HELPS

    CHEERS!!!


  2. Alright, so to find the concentration of a strong base (like NaOH), you want to find:

    Molarity = moles NaOH/liters of solution

    You know that you have 6 g of NaOH, so you need to convert to moles using the gram formula mass, which is 40 g/mol

    6 g NaOH  x  1 mol/40 g = 0.15 mol NaOH

    Good so far? Now, just plug that in to find the molarity:

    0.15 mol/ 1 L = 0.15 M

    Since NaOH is a strong base, it will dissolve completely in solution, so you will have [Na+]=0.15 M and [OH-]=0.15 M.

    To find the pOH, you follow the formula:

    pOH = -log[OH-]

    pOH=-log(.15)= 0.82

    pH + pOH must = 14, so:

    pH= 14- 0.82 = 13.18. A high pH is expected since this is a strong base and a higher pH indicates a higher basicity.

    Finally, since [H+][OH-] = 1 x 10^-14, plug in your [OH-] value and find [H+].

    Got it?

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