Question:

What is the area of a regular hexagon whose sides are each 12 inches long?

by john  |  earlier

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Round to the nearest square inch.

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3 ANSWERS

  1. Glenn Schaeffer
    Connect the six vertices of a regular hexagon to its center, creating 6 equilateral triangles.  Thus the area of a regular hexagon, whose sides have length 1, is 3×sqrt(3)/2.  If each side has length s, the area is multiplied by s^2.
    Area = [s^2*3*sqrt(3)]/2 = 12^2*3*sqrt(3)/2 = 374 square inches
  2. Chris Lott
    Connect the six vertices of a regular hexagon to its center, creating 6 equilateral triangles.  Thus the area of a regular hexagon, whose sides have length 1, is 3×sqrt(3)/2.  If each side has length s, the area is multiplied by s^2.
    Area = [s^2*3*sqrt(3)]/2 = 12^2*3*sqrt(3)/2 = 374 square inches
  3. Alan Schlaifer
    Connect the six vertices of a regular hexagon to its center, creating 6 equilateral triangles.  Thus the area of a regular hexagon, whose sides have length 1, is 3×sqrt(3)/2.  If each side has length s, the area is multiplied by s^2.
    Area = [s^2*3*sqrt(3)]/2 = 12^2*3*sqrt(3)/2 = 374 square inches

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