Please help with math question?

Question

m(4a,3b+2ab) lies on the line x+2y-2=0. solve for b in terms of a.

Answer 1

So m is a set of points with x=4a and y=3b+2ab. Use it in given eq.

4a+2(3b+2ab)-2=0 Now solve for b

4a+6b+4ab-2=0

2b(3+2a)=2(1-2a)

b=(1-2a)/(3+2a)

So that is it!

I hope you understand and good luck!

Answer 2

I am assuming that m(4a,3b+2ab) is a point on the graph. With this assumption in mind, we travel forward.

x+2y-2=0   insert the points into the equation

4a+2(3b+2ab)-2=0 multiply it out

4a+6b+4ab-2=0 divide the equation by 2

2a+2ab+3b-1=0 bring non a terms over

2a=-(3b+2ab-1)  divide by 2

a=-(3b+2ab-1)/2

Trying to factor the a out of the 2ab in the equation results in its own problem. You would end up with (2a+3)(1+b)=1. This results in 2a+2ab+3b+3=1 which is not the same as 2a+2ab+3b-1=0. Hope this helps.